Applied Mathematics for Class 11th & 12th (Concepts and Questions) | ||
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11th | Concepts | Questions |
12th | Concepts | Questions |
Content On This Page | ||
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Introduction to Sets – Definition | Representation of Sets | Types of Sets and Their Notations |
Subsets | Intervals | Venn Diagrams |
Operations on Sets |
Chapter 3 Sets (Concepts)
Welcome to a foundational exploration of Set Theory, a branch of mathematics that provides the essential language and structure for organizing information, defining relationships, and conducting logical analysis across countless disciplines. In Applied Mathematics, sets offer a precise way to group objects, model scenarios, and solve problems ranging from data analysis and probability to computer science and operations research. This chapter will furnish you with the core concepts, notation, operations, and problem-solving techniques associated with sets, building a critical foundation for understanding more advanced quantitative methods. Our focus will be on clarity, practical understanding, and the application of set principles to structure thought and solve problems effectively.
At its heart, a set is simply a well-defined collection of distinct objects, referred to as its elements or members. The 'well-defined' criterion is crucial; it means we must be able to definitively determine whether an object belongs to the set or not. We primarily use two methods to represent sets. The Roster form (or Tabular form) involves explicitly listing all the elements within curly braces, such as $\{a, e, i, o, u\}$. Alternatively, the Set-builder form (or Rule form) describes the elements by stating a common property they all share, for example, $\{x \mid x \text{ is a vowel in the English alphabet}\}$. Understanding both forms is essential for interpreting and defining sets accurately.
We encounter various types of sets, each with specific characteristics. The Empty Set, denoted by $\emptyset$ or $\left \{ \right \}$, is a set containing no elements at all. Sets can be finite (having a limited, countable number of elements) or infinite (having an unlimited number of elements). A singleton set contains just one element. We compare sets using concepts like equal sets (containing precisely the same elements) and equivalent sets (containing the same number of elements). The notion of inclusion is captured by subsets ($A \subseteq B$), meaning every element of set $A$ is also an element of set $B$. If $A$ is a subset of $B$ but $A$ is not equal to $B$, then $A$ is a proper subset ($A \subset B$). The set containing all possible elements relevant to a particular discussion is the Universal Set ($U$). Finally, the Power Set ($P(A)$) of a set $A$ is the set containing all possible subsets of $A$, including the empty set and the set $A$ itself.
Operating on sets allows us to combine or modify them in meaningful ways, often visualized using Venn diagrams. The key operations are:
- Union ($A \cup B$): The set of elements belonging to set $A$, or set $B$, or both.
- Intersection ($A \cap B$): The set of elements that are common to both set $A$ and set $B$.
- Difference ($A - B$): The set of elements that belong to set $A$ but do not belong to set $B$.
- Complement ($A'$ or $A^c$): The set of elements in the universal set $U$ that are not in set $A$.
A major practical application of set theory involves analyzing the cardinality of sets – the number of elements they contain, denoted by $n(A)$. The Principle of Inclusion-Exclusion provides formulas to calculate the cardinality of unions. For two sets, the formula is $n(A \cup B) = n(A) + n(B) - n(A \cap B)$. For three sets, it extends to $n(A \cup B \cup C) = n(A) + n(B) + n(C) - n(A \cap B) - n(B \cap C) - n(A \cap C) + n(A \cap B \cap C)$. These formulas are frequently applied to solve word problems, typically involving survey data where populations need to be classified based on multiple overlapping characteristics (e.g., people reading different newspapers, students playing different sports). Mastering these cardinality principles provides a powerful tool for quantitative analysis and logical problem-solving.
Introduction to Sets – Definition
In mathematics, the concept of a Set is fundamental and serves as a cornerstone for building more complex mathematical ideas. It is a primitive notion, meaning we do not define it formally using simpler terms, but rather describe it based on our intuitive understanding of grouping objects. Informally, a set is a collection of objects. However, for a collection to be considered a mathematical set, it must adhere to specific criteria, primarily being well-defined.
Definition of a Set
A Set is formally defined as a well-defined collection of distinct objects. Let's break down the crucial terms in this definition:
Well-defined: This is the most important characteristic of a set. A collection is well-defined if, given any object, we can unequivocally determine whether that object belongs to the collection or not. There should be no ambiguity, personal opinion, or subjective judgment involved in deciding membership. The criterion for inclusion must be clear and objective.
Distinct Objects: The objects within a set are considered unique. Even if an object is listed multiple times when describing a set, it is considered only once as an element of the set. The identity of the elements matters, not how many times they appear in a list. Also, the order in which elements are listed does not affect the set itself.
Understanding "Well-defined Collection"
To reiterate, a collection is well-defined if there is an unambiguous rule for membership. If the criteria for belonging to the collection are vague or depend on subjective factors, it is not a set in the mathematical sense.
Examples of Well-defined Collections (Sets):
The collection of all states in India. This is well-defined because the political boundaries and recognition of states are clearly defined by the Constitution of India. For any geographical area, we can definitively say if it is a state of India or not.
The collection of vowels in the English alphabet. This is well-defined; the vowels are precisely defined as {a, e, i, o, u}.
The collection of all natural numbers less than 10. This is well-defined; the natural numbers are $\{1, 2, 3, ...\}$, and the condition "less than 10" precisely identifies the elements {1, 2, 3, 4, 5, 6, 7, 8, 9}.
The collection of all rivers in India. While the exact definition of a river might sometimes be debated (e.g., seasonal rivers, tributaries), in a typical context, this collection is generally considered well-defined based on geographical surveys and common understanding.
The collection of solutions to the equation $x^2 - 4 = 0$. This is well-defined; the solutions are $x=2$ and $x=-2$. The set is $\{2, -2\}$.
Examples of Collections that are NOT Sets:
The collection of good students in a class. The term "good" is subjective. One person might consider "good" based on high marks, another based on behaviour, punctuality, or participation. There is no single, objective criterion that everyone would agree upon.
The collection of beautiful flowers in a garden. "Beautiful" is a matter of personal taste and perception, hence subjective and not well-defined.
The collection of rich people in a city. The term "rich" is relative and lacks a precise, universally agreed-upon definition (e.g., does it mean owning property above a certain value? Having an annual income above a specific amount? These thresholds are arbitrary unless explicitly defined for the context, but generally, the term itself is not mathematically precise).
The collection of interesting books in a library. "Interesting" is subjective and varies greatly from reader to reader.
The individual items or objects that constitute a set are called its elements or members. Sets are conventionally denoted by capital letters of the English alphabet (such as $A, B, C, X, Y, Z$), while the elements within a set are usually denoted by lowercase letters (like $a, b, c, x, y, z$) or numbers or other mathematical objects.
Membership Notation
To express whether a particular object is an element of a set, we use specific mathematical symbols:
The symbol $\in$ is used to indicate that an object belongs to or is an element of a set.
If $x$ is an element of a set $A$, we write it as $x \in A$.
This is read as "$x$ belongs to $A$" or "$x$ is an element of $A$".
The symbol $\notin$ is used to indicate that an object does not belong to or is not an element of a set.
If $y$ is not an element of a set $A$, we write it as $y \notin A$.
This is read as "$y$ does not belong to $A$" or "$y$ is not an element of $A$".
Example 1. Let $V$ be the set of vowels in the English alphabet.
Determine if 'a' is an element of $V$ and if 'z' is an element of $V$. Use appropriate notation.
Answer:
The set of vowels in the English alphabet is $V = \{a, e, i, o, u\}$.
We need to check if 'a' is present in this collection.
By definition, 'a' is one of the five English vowels, and it is listed as an element in the set $V$.
Therefore, 'a' belongs to the set $V$, which is written as $a \in V$.
Next, we check if 'z' is present in the set $V$.
By definition, 'z' is a consonant and is not one of the vowels {a, e, i, o, u}. It is not listed as an element in the set $V$.
Therefore, 'z' does not belong to the set $V$, which is written as $z \notin V$.
Example 2. Let $A = \{x \mid x \text{ is an even integer and } 1 < x < 10\}$.
Is 2 an element of $A$? Is 5 an element of $A$? Is 8 an element of $A$?
Answer:
The set $A$ is defined as the collection of all even integers that are strictly greater than 1 and strictly less than 10.
Let's list the elements that satisfy these conditions:
Integers between 1 and 10 are 2, 3, 4, 5, 6, 7, 8, 9.
Among these, the even integers are 2, 4, 6, 8.
So, the set $A$ can be written as $A = \{2, 4, 6, 8\}$.
Now, let's determine the membership for 2, 5, and 8:
Is 2 an element of $A$? Yes, 2 is an even integer, and $1 < 2 < 10$. 2 is listed in set $A$.
So, $2 \in A$.
Is 5 an element of $A$? 5 is an integer, and $1 < 5 < 10$. However, 5 is an odd integer, not an even integer. 5 is not listed in set $A$.
So, $5 \notin A$.
Is 8 an element of $A$? Yes, 8 is an even integer, and $1 < 8 < 10$. 8 is listed in set $A$.
So, $8 \in A$.
Representation of Sets
Once we understand what a set is (a well-defined collection of distinct objects), the next step is to learn how to represent or describe these sets. There are standard methods for writing down sets so that their elements are clearly identified. Primarily, there are two widely used methods for representing a set:
1. The Roster Method or Tabular Form.
2. The Set-Builder Method or Rule Method.
1. Roster Method (or Tabular Form)
In the Roster method, a set is represented by listing all its elements within curly braces `{}`. The elements are separated by commas. This method is also known as the Tabular form because it essentially presents the elements in a list or a table-like structure within the braces.
Key characteristics and conventions of Roster Form:
Listing Elements: All the elements belonging to the set are explicitly written out.
Enclosure: The list of elements is enclosed within a pair of curly braces, `{}`.
Separation: The elements are separated from each other by commas.
Order Does Not Matter: The order in which the elements are listed within the braces is immaterial. Changing the order of elements does not change the set. For example, the set containing the numbers 1, 2, and 3 can be written as $\{1, 2, 3\}$, $\{1, 3, 2\}$, $\{2, 1, 3\}$, $\{2, 3, 1\}$, $\{3, 1, 2\}$, or $\{3, 2, 1\}$. All these represent the same set.
Elements Are Distinct (No Repetition): Although the definition of a set specifies distinct objects, when listing elements in Roster form, if an object appears multiple times in the collection from which the set is formed, it is written only once in the set representation. Repetition of elements in the list does not add new elements to the set.
For example, consider the letters in the word "MATHEMATICS". The collection of letters is M, A, T, H, E, M, A, T, I, C, S. When represented as a set, repeated letters (M, A, T) are listed only once. The set of letters in the word "MATHEMATICS" is $\{M, A, T, H, E, I, C, S\}$. The order does not matter, so $\{A, C, E, H, I, M, S, T\}$ is the same set.
Example 1. Represent the set of even natural numbers less than 10 in Roster form.
Answer:
We are looking for natural numbers that are even and are strictly less than 10.
Natural numbers start from 1: $\{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ...\}$
Even numbers are integers divisible by 2: $\{..., -4, -2, 0, 2, 4, 6, 8, ...\}$
Even natural numbers are $\{2, 4, 6, 8, 10, 12, ...\}$
We need the ones less than 10. These are 2, 4, 6, and 8.
To represent this set in Roster form, we list these elements within curly braces, separated by commas.
The set is $\{2, 4, 6, 8\}$.
Let's denote this set by $E$. Then $E = \{2, 4, 6, 8\}$.
Example 2. Represent the set of prime numbers less than 20 in Roster form.
Answer:
A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.
We need to list all prime numbers that are strictly less than 20.
Starting from 2, the prime numbers are:
2 (only divisible by 1 and 2)
3 (only divisible by 1 and 3)
5 (only divisible by 1 and 5)
7 (only divisible by 1 and 7)
11 (only divisible by 1 and 11)
13 (only divisible by 1 and 13)
17 (only divisible by 1 and 17)
19 (only divisible by 1 and 19)
The next prime number is 23, which is not less than 20.
So, the prime numbers less than 20 are 2, 3, 5, 7, 11, 13, 17, and 19.
Representing this set in Roster form:
The set is $\{2, 3, 5, 7, 11, 13, 17, 19\}$.
Sometimes, for sets containing a large number of elements, especially infinite sets where the elements follow a clear pattern, we use an ellipsis (...) to indicate that the pattern continues. However, this is only permissible when the pattern is obvious and easily understandable from the first few listed elements.
- Example: The set of all natural numbers is $\{1, 2, 3, ...\}$. The pattern is adding 1 to the previous number.
- Example: The set of all integers is $\{..., -3, -2, -1, 0, 1, 2, 3, ...\}$. The pattern extends infinitely in both positive and negative directions.
- Example: The set of even integers is $\{..., -4, -2, 0, 2, 4, 6, ...\}$. The pattern is adding 2 to the previous number, extending infinitely.
If the pattern is not clear or the set is finite but very large with no obvious pattern, Roster form may not be practical or possible.
2. Set-Builder Method (or Rule Method)
The Set-Builder method represents a set by stating the characteristic property that all its elements must satisfy, and which no element outside the set satisfies. This method is particularly useful for describing sets that have too many elements to list in Roster form (like infinite sets) or when a specific property defines the set members. It is also known as the Rule method because it provides a rule for membership.
The general form of a set in Set-Builder notation is:
$\{x \mid \text{property } P(x) \text{ is true for } x\}$
Or sometimes a colon is used instead of the vertical bar:
$\{x : \text{property } P(x) \text{ is true for } x\}$
This notation is read as "the set of all elements $x$ such that $x$ has the property $P(x)$".
- The symbol $x$ is a variable representing any generic element of the set.
- The vertical bar ($|$) or colon (:) is read as "such that".
- The statement following the bar or colon is the property that defines the set. Only elements for which this property is true are members of the set.
Key characteristics and conventions of Set-Builder Form:
Property-Based Definition: The set is defined by a rule or property that its elements satisfy, rather than by listing them individually.
Conciseness: It provides a concise way to represent large or infinite sets.
Variable Representation: A variable is used as a placeholder for the elements.
Requires Understanding of Properties: To understand the set, one must understand the mathematical properties or conditions stated.
Example 3. Represent the set $A = \{1, 2, 3, 4, 5\}$ in Set-builder form.
Answer:
The elements of the set $A$ are the natural numbers from 1 to 5, inclusive.
We need to identify the property that these elements share.
Property: Each element $x$ is a natural number, and $x$ is less than or equal to 5.
Using Set-builder notation:
$A = \{x \mid x \text{ is a natural number and } x \leq 5\}$
Alternatively, using the symbol for the set of natural numbers ($\mathbb{N} = \{1, 2, 3, ...\}$):
$A = \{x \in \mathbb{N} \mid x \leq 5\}$
Both notations correctly describe the set $A$.
Example 4. Represent the set of all integers greater than $-3$ in Set-builder form.
Answer:
Let the set be denoted by $I$. The elements of this set are integers, and each integer must be strictly greater than $-3$.
The set of integers is denoted by $\mathbb{Z} = \{..., -3, -2, -1, 0, 1, 2, ...\}$.
The condition for membership is that an integer $x$ must satisfy $x > -3$.
In Set-builder form, we state this property:
$I = \{x \mid x \in \mathbb{Z} \text{ and } x > -3\}$
This set in Roster form would be $\{-2, -1, 0, 1, 2, 3, ...\}$, which is an infinite set. The Set-builder form provides a clear and concise way to describe this infinite set.
Example 5. Write the set $B = \{x \mid x = n^2 \text{ for } n \in \mathbb{N} \text{ and } n \leq 5\}$ in Roster form.
Answer:
The set $B$ consists of elements $x$ such that $x$ is the square of a natural number $n$, and $n$ is a natural number less than or equal to 5.
The possible values for $n$ are $1, 2, 3, 4, 5$.
We need to find the value of $x = n^2$ for each of these values of $n$:
- For $n=1$, $x = 1^2 = 1$.
- For $n=2$, $x = 2^2 = 4$.
- For $n=3$, $x = 3^2 = 9$.
- For $n=4$, $x = 4^2 = 16$.
- For $n=5$, $x = 5^2 = 25$.
The elements of the set $B$ are the calculated values of $x$: $\{1, 4, 9, 16, 25\}$.
Representing set $B$ in Roster form:
$B = \{1, 4, 9, 16, 25\}$
Types of Sets and Their Notations
Sets can be categorized into different types based on the number of elements they contain or based on specific properties of their elements. Understanding these different types and their standard notations is essential for working with sets.
1. Empty Set (or Null Set or Void Set)
A set that contains no elements at all is called the Empty Set. It is also known as the Null Set or the Void Set.
The Empty Set is a unique set, and it is denoted by the symbol $\emptyset$ (pronounced "phi") or by simply writing empty curly braces $\left \{ \right \}$. Both $\emptyset$ and $\left \{ \right \}$ represent the same set.
The cardinality (number of elements) of the empty set is 0, i.e., $n(\emptyset) = 0$.
Example 1. Give an example of an Empty Set.
Answer:
Consider the set of all real numbers $x$ such that $x^2 = -1$.
In Set-builder form, this set can be written as $\{x \in \mathbb{R} \mid x^2 = -1\}$, where $\mathbb{R}$ represents the set of all real numbers.
We know that for any real number $x$, its square ($x^2$) is always non-negative ($x^2 \geq 0$). There is no real number whose square is equal to $-1$.
Therefore, the collection of real numbers satisfying the condition $x^2 = -1$ contains no elements.
This set is the Empty Set, which can be denoted by $\emptyset$ or $\left \{ \right \}$.
Another example: The set of all natural numbers less than 1. Since natural numbers start from 1, there are no natural numbers that are strictly less than 1. So, this set is also the Empty Set.
2. Singleton Set
A set that contains exactly one element is called a Singleton Set.
For example, $\{5\}$ is a singleton set containing the number 5. $\{a\}$ is a singleton set containing the letter 'a'.
The cardinality of a singleton set is 1. If $A = \{x\}$, then $n(A) = 1$.
Example 2. Give examples of a Singleton Set.
Answer:
The set $\{0\}$. This set contains only one element, which is the number 0.
The set $\{x \in \mathbb{N} \mid 5 < x < 7\}$, where $\mathbb{N}$ is the set of natural numbers.
We need to find natural numbers that are greater than 5 and less than 7. The only natural number that fits this condition is 6.
So, this set is $\{6\}$. It contains exactly one element, 6. Therefore, it is a Singleton Set.
3. Finite Set
A set is classified as a Finite Set if it is either the Empty Set or if its elements can be counted completely, meaning that the process of counting the elements comes to an end. The number of elements in such a set is a non-negative integer.
The number of distinct elements in a finite set $A$ is called its cardinality or its order. It is denoted by $n(A)$ or $|A|$.
For example, if $A = \{1, 3, 5, 7\}$, the elements can be counted: there are 4 elements. So, $A$ is a finite set, and its cardinality is $n(A) = 4$.
Example 3. Give examples of Finite Sets and their cardinality.
Answer:
The set of days in a week. Let $W = \{ \text{Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday} \}$.
We can count the elements. There are 7 days in a week.
So, $W$ is a finite set, and its cardinality is $n(W) = 7$.
The set of students in your Class 11th (Applied Maths). Let this set be $C$. Assuming a typical class size, say 40 students, we can count all of them. So, $C$ is a finite set, and its cardinality is $n(C) = 40$.
The Empty Set $\emptyset$ is also considered a finite set because the number of elements is 0, which is a finite number. Its cardinality is $n(\emptyset) = 0$.
4. Infinite Set
A set that is not finite is called an Infinite Set. The elements of an infinite set cannot be counted completely; the process of listing or counting the elements would never come to an end.
Infinite sets can be of different sizes (cardinalities), but that is a concept explored in higher mathematics (countable vs. uncountable infinite sets). For Class 11, understanding that the number of elements is not finite is sufficient.
Example 4. Give examples of Infinite Sets.
Answer:
The set of all natural numbers: $\mathbb{N} = \{1, 2, 3, ...\}$. We can start listing natural numbers, but there is no largest natural number, so the list goes on infinitely.
The set of all integers: $\mathbb{Z} = \{..., -2, -1, 0, 1, 2, ...\}$. Integers extend infinitely in both positive and negative directions.
The set of all real numbers: $\mathbb{R}$. This set includes all rational and irrational numbers and is also an infinite set.
The set of all points on a line segment. Even a small line segment contains infinitely many points.
5. Equal Sets
Two sets, say $A$ and $B$, are said to be Equal Sets if they contain exactly the same elements. The order in which the elements are listed in Roster form or how many times an element is repeated does not affect the equality of sets.
If sets $A$ and $B$ are equal, we write $A = B$.
If they do not contain exactly the same elements, they are not equal, and we write $A \neq B$.
Equality of sets means that every element of set A is also an element of set B, AND every element of set B is also an element of set A.
Example 5. Are the sets $A = \{1, 2, 3\}$ and $B = \{3, 1, 2\}$ equal? Are the sets $C = \{1, 2, 3\}$ and $D = \{1, 2, 2, 3\}$ equal?
Answer:
For sets A and B:
Set A contains the elements 1, 2, and 3.
Set B contains the elements 3, 1, and 2.
Although the elements are listed in a different order, they are exactly the same set of distinct elements {1, 2, 3}. The order of elements does not matter in sets.
Therefore, sets A and B are equal: $A = B$.
For sets C and D:
Set C contains the elements 1, 2, and 3.
Set D is listed as $\{1, 2, 2, 3\}$. According to the definition of a set and its representation in Roster form, elements are distinct and repetition does not count as a new element. So, the distinct elements in set D are 1, 2, and 3.
Both sets C and D contain the same distinct elements {1, 2, 3}.
Therefore, sets C and D are equal: $C = D$.
6. Equivalent Sets
Two finite sets $A$ and $B$ are said to be Equivalent Sets if they have the same number of elements. In other words, two finite sets are equivalent if their cardinalities are equal.
We write $A \sim B$ or $A \equiv B$ if A and B are equivalent. This notation signifies that $n(A) = n(B)$.
The concept of equivalence relates to the size of the sets, not the identity of the elements. Two sets are equivalent if their elements can be put into a one-to-one correspondence (a bijection).
Important Note: If two sets are equal, they must have exactly the same elements, and therefore they must have the same number of elements. Thus, **Equal sets are always equivalent**. However, if two sets are equivalent, they only have the same number of elements; the elements themselves might be different. Thus, **Equivalent sets are not necessarily equal**.
Example 6. Are the sets $A = \{1, 2, 3\}$ and $B = \{a, b, c\}$ equivalent? Are they equal?
Answer:
For set A, the elements are 1, 2, and 3. The number of elements is $n(A) = 3$.
For set B, the elements are a, b, and c. The number of elements is $n(B) = 3$.
Since the number of elements in set A is equal to the number of elements in set B ($n(A) = n(B) = 3$), the sets A and B are equivalent.
Thus, $A \sim B$ (or $A \equiv B$).
Now let's check if sets A and B are equal. For sets to be equal, they must have exactly the same elements.
The elements of A are {1, 2, 3}. The elements of B are {a, b, c}.
The elements are different (e.g., 1 is in A but not in B; 'a' is in B but not in A).
Thus, $A \neq B$.
This example illustrates that two sets can be equivalent (same number of elements) without being equal (same specific elements).
7. Universal Set
In any particular context or problem in set theory, we often deal with elements that come from a larger, overarching set. This fundamental set, which contains all possible elements relevant to a specific discussion or problem, is called the Universal Set.
The Universal Set is typically denoted by the symbol $U$. It is not a fixed set; its definition depends entirely on the context of the problem you are working on. All other sets considered within that specific problem are assumed to be subsets of the Universal Set $U$.
Example 7. What could be a Universal Set for sets A = {vowels} and B = {consonants} in the English alphabet?
Answer:
Given the sets A (vowels) and B (consonants) are derived from the English alphabet, a suitable Universal Set $U$ encompassing all possible relevant elements in this context would be the set of all letters in the English alphabet.
$U = \{\text{all letters in the English alphabet}\}$
In Roster form, this would be $U = \{a, b, c, ..., z\}$.
Other examples of Universal Sets depending on the context:
- If you are discussing sets of natural numbers (e.g., set of even numbers, set of prime numbers), the set of all natural numbers ($\mathbb{N}$) or the set of all integers ($\mathbb{Z}$) or even the set of all real numbers ($\mathbb{R}$) could serve as the Universal Set, depending on how broadly you define the scope of elements you might consider.
- If you are discussing sets of students in a school, the set of all students in that school could be the Universal Set.
- If you are discussing sets of geometrical shapes within a plane, the set of all points in the plane could be the Universal Set.
The choice of the Universal Set is crucial as it defines the boundaries of the elements being considered in a particular problem.
Hierarchy of Number Systems within Real Numbers ($\mathbb{R}$)
When dealing with numbers, the Universal Set is often one of the standard sets of numbers. These sets are nested within each other, forming a hierarchy. The set of Real Numbers ($\mathbb{R}$) can be thought of as the largest of these common number sets used in pre-calculus mathematics.
1. Natural Numbers ($\mathbb{N}$)
These are the counting numbers, the most basic set of numbers.
$\mathbb{N} = \{1, 2, 3, 4, 5, ...\}$
Example Context: If we consider the set of prime numbers $P = \{2, 3, 5, 7, ...\}$, a suitable Universal Set would be $U = \mathbb{N}$.
2. Whole Numbers ($\mathbb{W}$)
This set includes all natural numbers and the number zero.
$\mathbb{W} = \{0, 1, 2, 3, 4, ...\}$
Relation: Every natural number is a whole number. Thus, $\mathbb{N} \subset \mathbb{W}$.
3. Integers ($\mathbb{Z}$)
This set includes all whole numbers and their negative counterparts.
$\mathbb{Z} = \{..., -3, -2, -1, 0, 1, 2, 3, ...\}$
Relation: Every whole number is an integer. Thus, $\mathbb{W} \subset \mathbb{Z}$.
Example Context: To find the solution for the equation $x + 5 = 2$, we get $x = -3$. If our Universal Set was $\mathbb{N}$ or $\mathbb{W}$, this equation would have no solution. A suitable Universal Set would be $U = \mathbb{Z}$.
4. Rational Numbers ($\mathbb{Q}$)
This set includes all numbers that can be expressed as a fraction $\frac{p}{q}$, where $p$ and $q$ are integers and $q \neq 0$. This includes all integers, terminating decimals, and repeating decimals.
Examples: $\frac{1}{2}, -7, 0.25, 0.\overline{3}$ (which is $\frac{1}{3}$)
Relation: Every integer can be written as a fraction with a denominator of 1 (e.g., $5 = \frac{5}{1}$). Thus, $\mathbb{Z} \subset \mathbb{Q}$.
Example Context: To solve the equation $3x = 7$, we get $x = \frac{7}{3}$. A suitable Universal Set would be $U = \mathbb{Q}$.
5. Irrational Numbers ($\mathbb{I}$ or $\mathbb{Q}'$)
This set includes all real numbers that cannot be expressed as a simple fraction. Their decimal representation is non-terminating and non-repeating.
Examples: $\sqrt{2}, \pi, e$ (Euler's number)
Relation: The set of rational numbers and the set of irrational numbers are disjoint, meaning they have no elements in common. $\mathbb{Q} \cap \mathbb{I} = \emptyset$.
6. Real Numbers ($\mathbb{R}$)
This set is the union of the set of rational numbers and the set of irrational numbers. It includes all numbers that can be represented on the number line.
Relation: $\mathbb{R} = \mathbb{Q} \cup \mathbb{I}$. Both rational and irrational numbers are subsets of real numbers. Thus, $\mathbb{Q} \subset \mathbb{R}$ and $\mathbb{I} \subset \mathbb{R}$.
Example Context: To solve the equation $x^2 = 2$, we get $x = \pm\sqrt{2}$. The solutions are irrational. The appropriate Universal Set for this problem is $U = \mathbb{R}$.
Summary of Relationships and Choice of Universal Set
The hierarchical relationship between these sets can be summarized as:
$\mathbb{N} \subset \mathbb{W} \subset \mathbb{Z} \subset \mathbb{Q} \subset \mathbb{R}$
The choice of Universal Set depends entirely on the scope of the problem:
- For problems involving only counting, $U = \mathbb{N}$ is sufficient.
- For problems where negative whole numbers are possible outcomes, $U = \mathbb{Z}$ is necessary.
- For problems involving division or ratios, $U = \mathbb{Q}$ is required.
- For problems in geometry or calculus that involve concepts like square roots of non-perfect squares or $\pi$, $U = \mathbb{R}$ is the standard choice.
Set Symbol | Name | Description | Example Elements |
---|---|---|---|
$\mathbb{N}$ | Natural Numbers | Counting numbers | $1, 5, 100$ |
$\mathbb{W}$ | Whole Numbers | Natural numbers including 0 | $0, 1, 5$ |
$\mathbb{Z}$ | Integers | Whole numbers and their negatives | $-3, 0, 7$ |
$\mathbb{Q}$ | Rational Numbers | Numbers expressible as a fraction $\frac{p}{q}$ | $\frac{1}{2}, -4, 0.\overline{3}$ |
$\mathbb{I}$ or $\mathbb{Q}'$ | Irrational Numbers | Non-terminating, non-repeating decimals | $\sqrt{2}, \pi, e$ |
$\mathbb{R}$ | Real Numbers | All numbers on the number line | $-5, 0, \frac{3}{4}, \sqrt{5}$ |
Subsets
The concept of a Subset establishes a fundamental relationship between two sets. It helps us describe situations where one collection of objects is entirely included within another collection.
Definition of a Subset
A set $A$ is said to be a Subset of a set $B$ if every element of set $A$ is also an element of set $B$.
In other words, set $A$ is a subset of set $B$ if there is no element in $A$ that is not also in $B$.
This relationship is denoted by the symbol $\subseteq$. We write $A \subseteq B$ to indicate that set $A$ is a subset of set $B$.
In precise mathematical notation, the definition can be stated as:
$A \subseteq B \iff (\forall x, \text{ if } x \in A, \text{ then } x \in B)$
This is read as "Set $A$ is a subset of set $B$ if and only if for all elements $x$, if $x$ belongs to $A$, then $x$ must also belong to $B$".
If set $A$ is not a subset of set $B$, it means that there is at least one element in $A$ which is not present in $B$. We denote this by $A \not\subseteq B$.
$A \not\subseteq B \iff (\exists x \text{ such that } x \in A \text{ and } x \notin B)$
This is read as "Set $A$ is not a subset of set $B$ if and only if there exists at least one element $x$ such that $x$ belongs to $A$ but $x$ does not belong to $B$".
Example 1. Let $A = \{1, 2\}$ and $B = \{1, 2, 3\}$. Is A a subset of B?
Answer:
To check if $A \subseteq B$, we need to verify if every element of set $A$ is also an element of set $B$.
The elements of set $A$ are 1 and 2.
Let's check each element:
Is 1 an element of $B = \{1, 2, 3\}$? Yes, $1 \in B$.
Is 2 an element of $B = \{1, 2, 3\}$? Yes, $2 \in B$.
Since both elements of A (1 and 2) are also present in set B, the condition for being a subset is met.
Therefore, A is a subset of B. We write $A \subseteq B$.
Example 2. Let $A = \{a, b\}$ and $B = \{b, c, d\}$. Is A a subset of B?
Answer:
To check if $A \subseteq B$, we need to verify if every element of set $A$ is also an element of set $B$.
The elements of set $A$ are 'a' and 'b'.
Let's check each element:
Is 'a' an element of $B = \{b, c, d\}$? No, 'a' is not present in set B ($a \notin B$).
Since we found at least one element in A ('a') that is not in B, the condition for being a subset is not met.
Therefore, A is not a subset of B. We write $A \not\subseteq B$.
Note: The element 'b' is in both A and B, but this is not sufficient for A to be a subset of B; *every* element of A must be in B.
Proper Subset
A set $A$ is said to be a Proper Subset of a set $B$ if $A$ is a subset of $B$ ($A \subseteq B$) and $A$ is not equal to $B$ ($A \neq B$).
This means that every element of $A$ is in $B$, and there is at least one element in $B$ that is not in $A$. In simpler terms, $A$ is contained within $B$, but $A$ and $B$ are not the same set.
We denote this relationship by $A \subset B$. Note the symbol is $\subset$ (without the underline), indicating strict inclusion.
In mathematical terms:
$A \subset B \iff (A \subseteq B \text{ and } A \neq B)$
Example 3. Let $A = \{1, 2\}$ and $B = \{1, 2, 3\}$. Is A a proper subset of B?
Answer:
To check if $A$ is a proper subset of $B$, we need to verify two conditions:
1. Is $A$ a subset of $B$ ($A \subseteq B$)?
As determined in Example 1, every element of A (1 and 2) is in B. So, $A \subseteq B$. (Condition 1 satisfied)
2. Is $A$ not equal to $B$ ($A \neq B$)?
$A = \{1, 2\}$ and $B = \{1, 2, 3\}$. Set B contains the element 3, which is not present in set A. Since they do not contain exactly the same elements, $A$ is not equal to $B$. (Condition 2 satisfied)
Since both conditions ($A \subseteq B$ and $A \neq B$) are satisfied, A is a proper subset of B.
We write $A \subset B$.
If $A = \{1, 2\}$ and $B = \{1, 2\}$, then $A \subseteq B$ (because every element of A is in B), but $A$ is not a proper subset of $B$ because $A = B$.
Superset
The term Superset is the inverse relationship of a subset. If set $A$ is a subset of set $B$ ($A \subseteq B$), then set $B$ is called a superset of set $A$.
We denote this by $B \supseteq A$, which reads as "$B$ is a superset of $A$".
$B \supseteq A \iff A \subseteq B$
Similarly, if $A$ is a proper subset of $B$ ($A \subset B$), then $B$ is called a Proper Superset of $A$. This means $B$ contains all elements of $A$ plus at least one more element.
We denote this by $B \supset A$, which reads as "$B$ is a proper superset of $A$".
$B \supset A \iff A \subset B$
Using Example 3 again: Since $A = \{1, 2\}$ is a proper subset of $B = \{1, 2, 3\}$, we can also say that $B$ is a proper superset of $A$, i.e., $B \supset A$.
Properties of Subsets
Several important properties arise from the definition of subsets:
Every set is a subset of itself: For any set $A$, $A \subseteq A$.
Explanation: By definition, $A \subseteq A$ if every element of $A$ is also an element of $A$. This is trivially true. For any $x$, if $x \in A$, then $x \in A$ is always true.
The empty set is a subset of every set: For any set $A$, $\emptyset \subseteq A$.
Explanation: By definition, $\emptyset \subseteq A$ if for every element $x$, if $x \in \emptyset$, then $x \in A$. Since the empty set $\emptyset$ contains no elements, the condition "$x \in \emptyset$" is always false. In logic, an implication "if P, then Q" is true whenever P is false. Thus, "if $x \in \emptyset$, then $x \in A$" is true for any $x$ and any set $A$. This is sometimes called vacuously true.
Transitive Property of Subsets: If set $A$ is a subset of set $B$ ($A \subseteq B$) and set $B$ is a subset of set $C$ ($B \subseteq C$), then set $A$ is a subset of set $C$ ($A \subseteq C$).
$(\text{If } A \subseteq B \text{ and } B \subseteq C) \implies A \subseteq C$
Explanation: Assume $A \subseteq B$ and $B \subseteq C$. Take any element $x \in A$. Since $A \subseteq B$, if $x \in A$, then $x \in B$. Now, since $x \in B$ and $B \subseteq C$, if $x \in B$, then $x \in C$. Combining these, if $x \in A$, then $x \in C$. This is the definition of $A \subseteq C$.
Set Equality in terms of Subsets: Two sets $A$ and $B$ are equal if and only if $A$ is a subset of $B$ and $B$ is a subset of $A$.
$A = B \iff (A \subseteq B \text{ and } B \subseteq A)$
Explanation: This property provides a rigorous way to prove that two sets are equal. It requires showing that every element of A is in B, and every element of B is in A.
Number of Subsets
For a finite set, we can determine exactly how many distinct subsets it has. If a finite set $A$ has $n(A) = m$ elements, the total number of possible subsets of $A$ is given by $2^m$.
$\text{Number of subsets of a set with } m \text{ elements} = 2^m$
Explanation for the formula $2^m$: Consider a set $A = \{a_1, a_2, ..., a_m\}$ with $m$ elements. To form a subset of $A$, for each element $a_i$, we have two choices: either include $a_i$ in the subset or do not include $a_i$. Since there are $m$ elements, and for each element there are 2 independent choices, the total number of ways to make these choices is $2 \times 2 \times ... \times 2$ ($m$ times), which equals $2^m$. Each unique combination of choices forms a unique subset.
The total number of proper subsets of a set $A$ with $n(A) = m$ elements is $2^m - 1$. This is because the only subset that is not a proper subset is the set $A$ itself ($A \subseteq A$ but $A \not\subset A$).
$\text{Number of proper subsets} = 2^m - 1$
Example 4. Find the number of subsets and proper subsets of the set $S = \{x, y, z\}$. List all the subsets.
Answer:
The given set is $S = \{x, y, z\}$.
First, find the number of elements in set $S$. $n(S) = 3$.
Using the formula for the number of subsets:
Number of subsets $= 2^{n(S)} = 2^3 = 8$.
Using the formula for the number of proper subsets:
Number of proper subsets $= 2^{n(S)} - 1 = 2^3 - 1 = 8 - 1 = 7$.
Now, let's list all the 8 subsets of S. We can list them based on the number of elements they contain:
- Subsets with 0 elements: The empty set $\emptyset$.
- Subsets with 1 element (Singleton sets): $\{x\}, \{y\}, \{z\}$.
- Subsets with 2 elements: $\{x, y\}, \{x, z\}, \{y, z\}$.
- Subsets with 3 elements: The set S itself $\{x, y, z\}$.
Listing all subsets:
The subsets of $S$ are: $\emptyset, \{x\}, \{y\}, \{z\}, \{x, y\}, \{x, z\}, \{y, z\}, \{x, y, z\}$.
Out of these, the proper subsets are all except $\{x, y, z\}$.
The proper subsets of $S$ are: $\emptyset, \{x\}, \{y\}, \{z\}, \{x, y\}, \{x, z\}, \{y, z\}$.
Power Set
The Power Set of a set $A$ is a special set that consists of all possible subsets of $A$. It is often described as the "set of all subsets." This means the elements of the power set are not individual items but are themselves sets.
The power set of $A$ is denoted by $\mathcal{P}(A)$ or $P(A)$.
Cardinality of a Power Set
If $A$ is a finite set with $n(A) = m$ elements, then the number of elements in its power set is equal to the total number of subsets of $A$, which is $2^m$.
$n(\mathcal{P}(A)) = 2^{n(A)} = 2^m$
Derivation of the Formula: To form any subset of $A$, we must decide for each of the $m$ elements whether to include it in the subset or not. For the first element, there are 2 choices (include or exclude). For the second element, there are also 2 choices, and so on for all $m$ elements. Since these choices are independent, the total number of possible combinations of choices is $2 \times 2 \times \dots \times 2$ ($m$ times), which is $2^m$. Each unique combination corresponds to a unique subset. Therefore, there are $2^m$ subsets in total.
Key Characteristics
- The empty set ($\emptyset$) is always a subset of any set $A$, so $\emptyset$ will always be an element of $\mathcal{P}(A)$.
- Any set $A$ is always a subset of itself, so $A$ will always be an element of $\mathcal{P}(A)$.
Important Distinction: Membership vs. Subset
It is crucial to understand the difference between an element belonging to a set ($\in$) and a set being a subset of another set ($\subseteq$).
Consider the set $A = \{1, 2\}$:
- $1 \in A$ (1 is an element of A).
- $\{1\} \subseteq A$ (The set containing 1 is a subset of A).
- $\{1\} \in \mathcal{P}(A)$ (The set containing 1 is an element of the power set of A).
- $1 \notin \mathcal{P}(A)$ (The number 1 itself is not an element of the power set of A; the elements of $\mathcal{P}(A)$ are sets).
Example 5. Find the power set of the set $A = \{1, 2\}$.
Answer:
Given: The set is $A = \{1, 2\}$.
Step 1: Determine the number of subsets.
The number of elements in set A is $n(A) = 2$.
Using the formula, the total number of subsets (and thus the number of elements in the power set) will be $2^{n(A)} = 2^2 = 4$.
Step 2: Systematically list all subsets of A.
We can organize the listing by the size of the subsets:
- Subsets with 0 elements: There is only one such subset, the empty set: $\emptyset$.
- Subsets with 1 element (singletons): We form a set for each individual element of A: $\{1\}$, $\{2\}$.
- Subsets with 2 elements: There is only one subset with all elements of A: $\{1, 2\}$ (which is the set A itself).
Step 3: Construct the power set.
The power set $\mathcal{P}(A)$ is the set containing all the subsets we listed in Step 2 as its elements. We enclose the collection of these subsets within a single pair of curly braces.
The subsets of A are $\emptyset, \{1\}, \{2\}, \{1, 2\}$.
Therefore, the power set is:
$\mathcal{P}(A) = \{\emptyset, \{1\}, \{2\}, \{1, 2\}\}$
Verification: The number of elements in our constructed power set is $n(\mathcal{P}(A)) = 4$, which matches the expected number calculated in Step 1.
Example 6. Find the power set of the empty set, $A = \emptyset$.
Answer:
Given: The set is $A = \emptyset = \{\}$.
Step 1: Determine the number of subsets.
The number of elements in the empty set is $n(A) = 0$.
Using the formula, the total number of subsets will be $2^{n(A)} = 2^0 = 1$.
Step 2: List all subsets of A.
The only subset of the empty set is the empty set itself. This is because the property "the empty set is a subset of every set" applies here as well.
So, the only subset is $\emptyset$.
Step 3: Construct the power set.
The power set $\mathcal{P}(A)$ is the set containing this one subset as its element.
$\mathcal{P}(\emptyset) = \{\emptyset\}$
Verification: The number of elements in $\mathcal{P}(\emptyset)$ is 1, which matches our calculation. It's important to note that the power set of the empty set is not empty; it is a set containing one element (that element being the empty set).
Example 7. Find the power set of the set $B = \{a\}$.
Answer:
Given: The set is $B = \{a\}$.
Step 1: Determine the number of subsets.
The number of elements in set B is $n(B) = 1$.
Using the formula, the total number of subsets will be $2^{n(B)} = 2^1 = 2$.
Step 2: Systematically list all subsets of B.
- Subsets with 0 elements: The empty set, $\emptyset$.
- Subsets with 1 element: The set itself, $\{a\}$.
The two subsets of B are $\emptyset$ and $\{a\}$.
Step 3: Construct the power set.
The power set $\mathcal{P}(B)$ is the set containing these two subsets as its elements.
$\mathcal{P}(B) = \{\emptyset, \{a\}\}$
Verification: The number of elements in $\mathcal{P}(B)$ is 2, which matches our calculation.
Example 8. Find the power set of the set $C = \{x, y, z\}$.
Answer:
Given: The set is $C = \{x, y, z\}$.
Step 1: Determine the number of subsets.
The number of elements in set C is $n(C) = 3$.
Using the formula, the total number of subsets will be $2^{n(C)} = 2^3 = 8$.
Step 2: Systematically list all subsets of C.
- Subsets with 0 elements: $\emptyset$.
- Subsets with 1 element: $\{x\}$, $\{y\}$, $\{z\}$.
- Subsets with 2 elements: $\{x, y\}$, $\{x, z\}$, $\{y, z\}$.
- Subsets with 3 elements: $\{x, y, z\}$.
We have listed all 8 subsets.
Step 3: Construct the power set.
The power set $\mathcal{P}(C)$ is the set containing all 8 of these subsets as its elements.
$\mathcal{P}(C) = \{\emptyset, \{x\}, \{y\}, \{z\}, \{x, y\}, \{x, z\}, \{y, z\}, \{x, y, z\}\}$
Verification: The number of elements in $\mathcal{P}(C)$ is 8, which matches our calculation.
Intervals
In mathematics, particularly when working with real numbers, intervals are special types of subsets of the set of real numbers ($\mathbb{R}$). An interval represents a contiguous range of real numbers between two given endpoints. These endpoints can either be included in the set or excluded, leading to different types of intervals. Intervals are commonly used to express the solution sets of inequalities or to define domains and ranges of functions.
Types of Intervals
Let $a$ and $b$ be two real numbers such that $a < b$. These numbers serve as the endpoints of the interval. Based on whether these endpoints are included or excluded, we define different types of finite intervals:
1. Closed Interval
A Closed Interval consists of all real numbers $x$ that are greater than or equal to the left endpoint $a$ and less than or equal to the right endpoint $b$. Both endpoints, $a$ and $b$, are included in the interval.
Notation: The closed interval is denoted by square brackets enclosing the endpoints: $[a, b]$.
Set-builder form: Using set-builder notation, the closed interval $[a, b]$ is written as $\{x \in \mathbb{R} \mid a \leq x \leq b\}$.
Representation on number line: On a number line, a closed interval is represented by a line segment connecting the endpoints, with solid (filled) dots at $a$ and $b$ to indicate that these points are included in the interval.
2. Open Interval
An Open Interval consists of all real numbers $x$ that are strictly greater than the left endpoint $a$ and strictly less than the right endpoint $b$. The endpoints $a$ and $b$ are NOT included in the interval.
Notation: The open interval is denoted by parentheses enclosing the endpoints: $(a, b)$. Some texts also use reversed square brackets: $]a, b[$. Both notations represent the same open interval.
Set-builder form: Using set-builder notation, the open interval $(a, b)$ is written as $\{x \in \mathbb{R} \mid a < x < b\}$.
Representation on number line: On a number line, an open interval is represented by a line segment connecting the endpoints, with hollow (unfilled) circles or parentheses at $a$ and $b$ to indicate that these points are excluded from the interval.
3. Semi-open or Semi-closed Intervals
These intervals include exactly one of the two endpoints. They are sometimes referred to as half-open or half-closed intervals.
Left-closed, Right-open Interval:
This interval consists of all real numbers $x$ such that $x$ is greater than or equal to the left endpoint $a$ and strictly less than the right endpoint $b$. The endpoint $a$ is included, while the endpoint $b$ is not.
Notation: $[a, b)$.
Set-builder form: $\{x \in \mathbb{R} \mid a \leq x < b\}$.
Representation on number line: A line segment with a solid dot at $a$ and a hollow circle (or parenthesis) at $b$.
Left-open, Right-closed Interval:
This interval consists of all real numbers $x$ such that $x$ is strictly greater than the left endpoint $a$ and less than or equal to the right endpoint $b$. The endpoint $a$ is not included, while the endpoint $b$ is included.
Notation: $(a, b]$.
Set-builder form: $\{x \in \mathbb{R} \mid a < x \leq b\}$.
Representation on number line: A line segment with a hollow circle (or parenthesis) at $a$ and a solid dot at $b$.
Infinite Intervals
Intervals can also extend infinitely in one or both directions along the real number line. These intervals use the symbols for positive infinity ($\infty$) and negative infinity ($-\infty$). Note that $\infty$ and $-\infty$ are not real numbers, so they are always associated with an open boundary (parenthesis).
$[a, \infty)$: The set of all real numbers $x$ such that $x$ is greater than or equal to $a$. $\{x \in \mathbb{R} \mid x \geq a\}$.
$(a, \infty)$: The set of all real numbers $x$ such that $x$ is strictly greater than $a$. $\{x \in \mathbb{R} \mid x > a\}$.
$(-\infty, b]$: The set of all real numbers $x$ such that $x$ is less than or equal to $b$. $\{x \in \mathbb{R} \mid x \leq b\}$.
$(-\infty, b)$: The set of all real numbers $x$ such that $x$ is strictly less than $b$. $\{x \in \mathbb{R} \mid x < b\}$.
$(-\infty, \infty)$: The set of all real numbers. $\{x \in \mathbb{R}\}$. This represents the entire number line, $\mathbb{R}$.
Relationship between Intervals and Inequalities
Interval notation is a convenient shorthand for expressing inequalities involving real numbers.
Inequality | Type of Interval | Interval Notation | Set-Builder Notation |
---|---|---|---|
$a \leq x \leq b$ | Closed | $[a, b]$ | $\{x \in \mathbb{R} \mid a \leq x \leq b\}$ |
$a < x < b$ | Open | $(a, b)$ | $\{x \in \mathbb{R} \mid a < x < b\}$ |
$a \leq x < b$ | Semi-open/closed | $[a, b)$ | $\{x \in \mathbb{R} \mid a \leq x < b\}$ |
$a < x \leq b$ | Semi-open/closed | $(a, b]$ | $\{x \in \mathbb{R} \mid a < x \leq b\}$ |
$x \geq a$ | Infinite (closed) | $[a, \infty)$ | $\{x \in \mathbb{R} \mid x \geq a\}$ |
$x > a$ | Infinite (open) | $(a, \infty)$ | $\{x \in \mathbb{R} \mid x > a\}$ |
$x \leq b$ | Infinite (closed) | $(-\infty, b]$ | $\{x \in \mathbb{R} \mid x \leq b\}$ |
$x < b$ | Infinite (open) | $(-\infty, b)$ | $\{x \in \mathbb{R} \mid x < b\}$ |
Any real number | Infinite (open) | $(-\infty, \infty)$ | $\{x \in \mathbb{R}\}$ |
Example 1. Write the interval corresponding to the set $\{x \in \mathbb{R} \mid -2 < x \leq 5\}$.
Answer:
The given set-builder form is $\{x \in \mathbb{R} \mid -2 < x \leq 5\}$.
This describes all real numbers $x$ such that $x$ is strictly greater than $-2$ and less than or equal to 5.
The left inequality, $x > -2$, indicates that the left endpoint $-2$ is not included, which corresponds to an open boundary represented by a parenthesis '('.
The right inequality, $x \leq 5$, indicates that the right endpoint 5 is included, which corresponds to a closed boundary represented by a square bracket ']'.
The interval starts at $-2$ (exclusive) and ends at 5 (inclusive).
Therefore, the corresponding interval notation is $(-2, 5]$.
Example 2. Write the set-builder form for the interval $[-1, 7)$.
Answer:
The given interval is $[-1, 7)$.
This notation represents a left-closed, right-open interval.
The square bracket '[' on the left side of $-1$ means that $-1$ is included in the interval ($x \geq -1$).
The parenthesis ')' on the right side of 7 means that 7 is not included in the interval ($x < 7$).
So, the interval includes all real numbers $x$ that satisfy both $x \geq -1$ and $x < 7$. This can be written as a compound inequality: $-1 \leq x < 7$.
The elements of the interval are real numbers ($\in \mathbb{R}$).
Combining these, the set-builder form is:
$\{x \in \mathbb{R} \mid -1 \leq x < 7\}$
Example 3. Represent the inequality $x \geq 10$ using interval notation and set-builder form, and describe it on a number line.
Answer:
The given inequality is $x \geq 10$. This means $x$ can be 10 or any real number greater than 10.
This is an infinite interval starting at 10 and extending to positive infinity.
The endpoint 10 is included (due to $\geq$), so we use a square bracket '[' at 10.
The interval extends to positive infinity ($\infty$), which always uses a parenthesis ')'.
Interval Notation: $[10, \infty)$.
In set-builder form, we describe the property the real numbers $x$ must satisfy:
Set-builder Form: $\{x \in \mathbb{R} \mid x \geq 10\}$.
Representation on number line: Draw a number line. Place a solid dot at 10 and draw an arrow extending from this dot to the right, covering all numbers greater than 10.
Venn Diagrams
When working with sets, especially when dealing with relationships between multiple sets or performing operations on them, visual representation can be extremely helpful. Venn Diagrams are graphical illustrations used to show the relationships between sets and their elements. They provide a simple and intuitive way to understand set theory concepts and solve problems involving set operations. These diagrams were introduced by the English logician and philosopher John Venn in the late 19th century.
Components of a Venn Diagram
A typical Venn diagram consists of the following components:
1. Universal Set (U)
The Universal Set, which represents the entire scope of elements under consideration for a particular problem, is usually depicted by a large rectangle. All other sets discussed in the problem are considered to be subsets of this Universal Set. The area within the rectangle represents all the elements in the Universal Set $U$.
2. Sets (Subsets of U)
Individual sets that are subsets of the Universal Set are commonly represented by circles or ovals drawn within the rectangle. Each circle represents a specific set, and the elements belonging to that set are considered to be inside that circle.
3. Elements
The specific elements of the sets are indicated as points within the corresponding regions. If an element belongs to multiple sets, it is placed in the overlapping region. If an element is in the Universal Set but not in any of the specific sets, it is placed within the rectangle but outside all the circles.

In the diagram above, for $U=\{1,2,3,4,5,6,7,8\}$, $A=\{1,2,3\}$ and $B=\{3,4,5\}$, the elements are placed in their respective regions.
Representing Set Relationships using Venn Diagrams
Venn diagrams are powerful tools for visually depicting the relationships between two or more sets:
1. Disjoint Sets
Two sets $A$ and $B$ are said to be disjoint sets if they have no elements in common. Their intersection is the empty set. In a Venn diagram, disjoint sets are represented by two circles that do not overlap at all.
$A \cap B = \emptyset$

Example: If $A = \{1, 2\}$ and $B = \{3, 4\}$, the circles for A and B would be separate.
2. Intersecting Sets
Two sets $A$ and $B$ are called intersecting sets if they have at least one element in common. In a Venn diagram, this is shown by two overlapping circles. The overlapping region represents the elements common to both sets, i.e., the intersection $A \cap B$.
$A \cap B \neq \emptyset$

Example: If $A = \{1, 2, 3\}$ and $B = \{2, 3, 4\}$, the overlapping region would contain elements 2 and 3.
3. Subset
If set $A$ is a subset of set $B$, every element of $A$ is also an element of $B$. This is shown by drawing the circle for set $A$ completely inside the circle for set $B$.
$A \subseteq B$

Example: If $A = \{1, 2\}$ and $B = \{1, 2, 3\}$, the circle for A would be inside the circle for B.
Representing Set Operations using Venn Diagrams
Venn diagrams are especially useful for visualizing the outcome of set operations. The result of an operation is typically shown by shading the relevant region(s).
1. Union of Sets ($A \cup B$)
The union of sets A and B contains all elements that are in A, or in B, or in both. The shaded region covers both circles entirely.
$A \cup B = \{x \mid x \in A \text{ or } x \in B\}$

2. Intersection of Sets ($A \cap B$)
The intersection of sets A and B contains only the elements that are common to both A and B. The shaded region is the overlapping part of the two circles.
$A \cap B = \{x \mid x \in A \text{ and } x \in B\}$

3. Difference of Sets ($A - B$)
The difference A - B contains the elements that are in A but not in B. The shaded region is the part of circle A that does not overlap with circle B.
$A - B = \{x \mid x \in A \text{ and } x \notin B\}$

4. Complement of a Set ($A'$)
The complement of set A contains all elements in the Universal Set U that are not in A. The shaded region is the area inside the rectangle but outside of circle A.
$A' = \{x \in U \mid x \notin A\}$

Operations on Sets
Just as we perform arithmetic operations like addition, subtraction, multiplication, and division on numbers to combine or compare them, we can also perform operations on sets. These set operations allow us to combine sets, find common elements, or find elements present in one set but not another. Understanding these operations is crucial for solving problems involving sets and for building more complex set-theoretic concepts.
Throughout this discussion on set operations, let $U$ denote the Universal Set (the set of all elements under consideration in a given context), and let $A$ and $B$ be any two subsets of $U$.
1. Union of Sets
The Union of two sets $A$ and $B$ is a new set that contains all the elements that are in set $A$ or in set $B$ or in both sets $A$ and $B$. In simpler terms, it is the collection of all elements from both sets combined, with common elements listed only once (as elements in a set must be distinct).
The union of sets $A$ and $B$ is denoted by the symbol $\cup$. We write it as $A \cup B$.
In Set-builder form, the definition of the union of two sets is:
$A \cup B = \{x \mid x \in A \text{ or } x \in B\}$
This is read as "the set of all elements $x$ such that $x$ is an element of $A$ or $x$ is an element of $B$". Note that the word "or" in mathematics is typically used in the inclusive sense, meaning "A or B or both".
Example 1. Let $A = \{1, 2, 3\}$ and $B = \{3, 4, 5\}$. Find $A \cup B$.
Answer:
The set $A$ contains the elements 1, 2, and 3.
The set $B$ contains the elements 3, 4, and 5.
The union $A \cup B$ includes all elements that are in A or in B. We list all the elements from A and all elements from B, ensuring that any common elements are only listed once.
Elements from A: 1, 2, 3
Elements from B: 3, 4, 5
Combining these lists and removing duplicates (the number 3 is common): 1, 2, 3, 4, 5.
Therefore, $A \cup B = \{1, 2, 3, 4, 5\}$.
Note that the common element 3 appears only once in the resulting set.
2. Intersection of Sets
The Intersection of two sets $A$ and $B$ is a new set that contains only those elements that are common to both set $A$ and set $B$.
The intersection of sets $A$ and $B$ is denoted by the symbol $\cap$. We write it as $A \cap B$.
In Set-builder form, the definition of the intersection of two sets is:
$A \cap B = \{x \mid x \in A \text{ and } x \in B\}$
This is read as "the set of all elements $x$ such that $x$ is an element of $A$ and $x$ is an element of $B$".
Example 2. Let $A = \{1, 2, 3, 4\}$ and $B = \{3, 4, 5, 6\}$. Find $A \cap B$.
Answer:
The set $A$ contains the elements 1, 2, 3, and 4.
The set $B$ contains the elements 3, 4, 5, and 6.
The intersection $A \cap B$ includes only those elements that are present in both set A and set B.
Comparing the elements, we see that 3 is in both A and B, and 4 is also in both A and B.
Elements 1 and 2 are only in A. Elements 5 and 6 are only in B.
Therefore, $A \cap B = \{3, 4\}$.
If two sets have no elements in common, their intersection is the Empty Set. Such sets are called Disjoint Sets.
Sets $A$ and $B$ are disjoint $\iff A \cap B = \emptyset$
Example: If $A = \{1, 2\}$ and $B = \{3, 4\}$, then $A \cap B = \emptyset$. Sets A and B are disjoint.
3. Difference of Sets
The Difference of set $A$ and set $B$ (in that order) is the set containing all the elements that are in set $A$ but are not in set $B$.
The difference of set $A$ and set $B$ is denoted by $A - B$ or $A \setminus B$.
In Set-builder form, the definition is:
$A - B = \{x \mid x \in A \text{ and } x \notin B\}$
This is read as "the set of all elements $x$ such that $x$ is an element of $A$ and $x$ is not an element of $B$".
Similarly, the difference of set $B$ and set $A$, denoted by $B - A$, is the set of elements that are in $B$ but not in $A$.
$B - A = \{x \mid x \in B \text{ and } x \notin A\}$
It is important to note that generally, $A - B$ is not equal to $B - A$.
Example 3. Let $A = \{1, 2, 3, 4\}$ and $B = \{3, 4, 5, 6\}$. Find $A - B$ and $B - A$.
Answer:
For $A - B$, we need to find elements that are in set $A$ but are not in set $B$.
Set A elements: 1, 2, 3, 4.
Set B elements: 3, 4, 5, 6.
Elements in A: 1 (not in B), 2 (not in B), 3 (is in B), 4 (is in B).
The elements that are in A but not in B are 1 and 2.
Therefore, $A - B = \{1, 2\}$.
For $B - A$, we need to find elements that are in set $B$ but are not in set $A$.
Set B elements: 3, 4, 5, 6.
Set A elements: 1, 2, 3, 4.
Elements in B: 3 (is in A), 4 (is in A), 5 (not in A), 6 (not in A).
The elements that are in B but not in A are 5 and 6.
Therefore, $B - A = \{5, 6\}$.
As expected, $A - B \neq B - A$ in this case.
4. Complement of a Set
The Complement of a set $A$ is the set containing all the elements in the Universal Set $U$ that are not in set $A$. The complement of $A$ depends on the definition of the Universal Set for that particular problem.
The complement of set $A$ is denoted by $A'$ or $A^c$ or $\overline{A}$.
In Set-builder form, the definition of the complement of a set is:
$A' = \{x \mid x \in U \text{ and } x \notin A\}$
This is read as "the set of all elements $x$ such that $x$ is an element of the Universal Set $U$ and $x$ is not an element of $A$".
From the definition, we can see that the complement of $A$ is equivalent to the difference between the Universal Set and the set $A$:
$A' = U - A$
Example 4. Let $U = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}$ be the Universal Set and $A = \{2, 4, 6, 8, 10\}$. Find $A'$.
Answer:
Given Universal Set $U = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}$.
Given set $A = \{2, 4, 6, 8, 10\}$.
The complement $A'$ consists of all elements in $U$ that are not in $A$. We look at the elements in $U$ and exclude those that are also in $A$.
Elements in U: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10.
Elements in A: 2, 4, 6, 8, 10.
Elements in U that are not in A are 1, 3, 5, 7, and 9.
Therefore, $A' = \{1, 3, 5, 7, 9\}$.
Properties and Laws of Set Operations
Set operations obey various laws, which are analogous to the laws of algebra for numbers. These laws are useful for simplifying expressions involving sets and proving set identities.
Idempotent Laws: Performing the union or intersection of a set with itself results in the same set.
$A \cup A = A$
$A \cap A = A$
Identity Laws: These involve the empty set ($\emptyset$) and the universal set ($U$).
$A \cup \emptyset = A$
$A \cap U = A$
$A \cap \emptyset = \emptyset$
$A \cup U = U$
Commutative Laws: The order of sets in union and intersection operations does not affect the result.
$A \cup B = B \cup A$
$A \cap B = B \cap A$
Associative Laws: When performing union or intersection with three or more sets, the grouping of sets does not affect the result.
$(A \cup B) \cup C = A \cup (B \cup C)$
$(A \cap B) \cap C = A \cap (B \cap C)$
Distributive Laws: These laws show how union and intersection interact with each other.
$A \cup (B \cap C) = (A \cup B) \cap (A \cup C)$
$A \cap (B \cup C) = (A \cap B) \cup (A \cap C)$
De Morgan's Laws: These laws relate the complement of unions and intersections to the complements of the individual sets.
$(A \cup B)' = A' \cap B'$
$(A \cap B)' = A' \cup B'$
Complement Laws: These involve the relationship between a set and its complement with respect to the universal set.
$A \cup A' = U$
$A \cap A' = \emptyset$
$(A')' = A$
(The complement of the complement of a set is the set itself)
$\emptyset' = U$
(The complement of the empty set is the universal set)
$U' = \emptyset$
(The complement of the universal set is the empty set)
Difference in terms of Complement and Intersection: The difference $A-B$ can also be expressed using complement and intersection.
$A - B = A \cap B'$
Explanation: $A-B$ consists of elements in A but not in B. $B'$ consists of elements not in B. $A \cap B'$ consists of elements that are in A AND not in B. This matches the definition of $A-B$.
Formulae for Number of Elements (Cardinality)
When dealing with finite sets, we are often interested in the number of elements in the sets resulting from set operations. These formulae are particularly useful in solving practical problems involving surveys or data classification.
Principle of Inclusion-Exclusion for Two Sets
For any two finite sets $A$ and $B$, the number of elements in their union, $n(A \cup B)$, is given by the formula:
$n(A \cup B) = n(A) + n(B) - n(A \cap B)$
Derivation:
Consider the elements in $A \cup B$. These elements can be in $A$ only, in $B$ only, or in both $A$ and $B$.
When we add $n(A)$ and $n(B)$, the elements that are in both sets (i.e., in $A \cap B$) are counted twice – once as part of $n(A)$ and once as part of $n(B)$.
To get the correct count of distinct elements in $A \cup B$, we add the counts of elements in $A$ and $B$ and then subtract the count of elements that were double-counted, which are the elements in the intersection $A \cap B$.
$n(A \cup B) = n(A \text{ only}) + n(B \text{ only}) + n(A \cap B)$
We know that $n(A) = n(A \text{ only}) + n(A \cap B)$, so $n(A \text{ only}) = n(A) - n(A \cap B)$.
We also know that $n(B) = n(B \text{ only}) + n(A \cap B)$, so $n(B \text{ only}) = n(B) - n(A \cap B)$.
Substituting these into the formula for $n(A \cup B)$:
$n(A \cup B) = (n(A) - n(A \cap B)) + (n(B) - n(A \cap B)) + n(A \cap B)$
$= n(A) + n(B) - n(A \cap B) - n(A \cap B) + n(A \cap B)$
$= n(A) + n(B) - n(A \cap B)$
This confirms the formula.
If sets $A$ and $B$ are disjoint, meaning $A \cap B = \emptyset$, then the number of elements in their intersection is $n(A \cap B) = 0$. In this special case, the formula for the union simplifies to:
If $A \cap B = \emptyset$, then $n(A \cup B) = n(A) + n(B)$
Formulae for Difference and Complement Cardinality
The number of elements in the difference of two sets can also be expressed in terms of cardinality:
$n(A - B) = n(A) - n(A \cap B)$
Derivation:
Set A can be partitioned into two disjoint parts: the elements that are only in A ($A-B$) and the elements that are in both A and B ($A \cap B$).
$A = (A - B) \cup (A \cap B)$
The sets $(A-B)$ and $(A \cap B)$ are disjoint (an element cannot be only in A AND in both A and B simultaneously). Since they are disjoint, we can use the simple union formula for their cardinalities:
$n(A) = n(A - B) + n(A \cap B)$
Rearranging the formula to solve for $n(A - B)$:
$n(A - B) = n(A) - n(A \cap B)$
This formula states that the number of elements in A only is the total number of elements in A minus the number of elements that are also in B.
Similarly, the number of elements in the complement of a set A with respect to a universal set $U$ is the total number of elements in $U$ minus the number of elements in A:
$n(A') = n(U) - n(A)$
Derivation:
The universal set $U$ can be partitioned into two disjoint parts: the elements that are in A, and the elements that are not in A ($A'$).
$U = A \cup A'$
Also, a set and its complement are always disjoint:
$A \cap A' = \emptyset$
Since $A$ and $A'$ are disjoint and their union is $U$, we can use the simple union formula for disjoint sets:
$n(U) = n(A) + n(A')$
Rearranging to solve for $n(A')$:
$n(A') = n(U) - n(A)$
This confirms the formula for the cardinality of the complement.
The union of two sets can also be expressed as the sum of the number of elements in $A$ only, $B$ only, and the number of elements in their intersection:
$n(A \cup B) = n(A - B) + n(B - A) + n(A \cap B)$
Explanation: The sets $(A-B)$, $(B-A)$, and $(A \cap B)$ are mutually disjoint regions that together form $A \cup B$. Summing their cardinalities gives the total cardinality of the union.
Principle of Inclusion-Exclusion for Three Sets
For three finite sets $A$, $B$, and $C$, the number of elements in their union is given by:
$n(A \cup B \cup C) = n(A) + n(B) + n(C) - n(A \cap B) - n(B \cap C) - n(A \cap C) + n(A \cap B \cap C)$
Explanation: When we sum $n(A) + n(B) + n(C)$, elements in pairwise intersections are counted twice. We subtract $n(A \cap B)$, $n(B \cap C)$, and $n(A \cap C)$ to correct this. However, the elements in the intersection of all three sets ($A \cap B \cap C$) were counted three times initially and then subtracted three times, resulting in a count of zero for that region. Therefore, we must add back $n(A \cap B \cap C)$ once to get the correct total.
Example 5. In a survey of 100 students, the number of students studying Mathematics is 50, the number of students studying Physics is 40, and the number of students studying both Mathematics and Physics is 20. Find the number of students studying either Mathematics or Physics.
Answer:
Let $U$ be the set of all students surveyed. So, $n(U) = 100$.
Let $M$ be the set of students studying Mathematics.
Let $P$ be the set of students studying Physics.
Given information:
$n(M) = 50$
$n(P) = 40$
The number of students studying both Mathematics and Physics corresponds to the intersection of sets M and P.
$n(M \cap P) = 20$
(Students studying both subjects)
We need to find the number of students studying either Mathematics or Physics. This corresponds to the union of sets M and P, i.e., $n(M \cup P)$.
Using the Principle of Inclusion-Exclusion for two sets:
$n(M \cup P) = n(M) + n(P) - n(M \cap P)$
Substitute the given values into the formula:
$n(M \cup P) = 50 + 40 - 20$
Perform the addition and subtraction:
$= 90 - 20$
$= 70$
... (i)
The number of students studying either Mathematics or Physics is 70.
Additional Question: Find the number of students studying exactly one of the two subjects.
The number of students studying exactly Mathematics is $n(M \text{ only}) = n(M - P) = n(M) - n(M \cap P) = 50 - 20 = 30$.
The number of students studying exactly Physics is $n(P \text{ only}) = n(P - M) = n(P) - n(M \cap P) = 40 - 20 = 20$.
The number of students studying exactly one subject is $n(M \text{ only}) + n(P \text{ only}) = 30 + 20 = 50$.
Alternatively, using Formula 31: $n(M \cup P) = n(M-P) + n(P-M) + n(M \cap P)$.
$70 = n(M-P) + n(P-M) + 20$.
$n(M-P) + n(P-M) = 70 - 20 = 50$. This is the number of students studying exactly one of the subjects.
Additional Question: Find the number of students studying neither Mathematics nor Physics.
Students studying neither subject are those in the Universal Set but not in the union of M and P. This is the complement of $M \cup P$ with respect to $U$, i.e., $(M \cup P)'$.
Using Formula 30: $n((M \cup P)') = n(U) - n(M \cup P)$.
$n((M \cup P)') = 100 - 70$
[From Given and (i)]
$= 30$
... (ii)
The number of students studying neither Mathematics nor Physics is 30.